Answer :
Answer:
The displacement current between the plates is [tex]1.26 \times 10^{-5}[/tex] mA
Explanation:
Given :
Potential difference [tex]\frac{dV}{dt} = 107[/tex] [tex]\frac{V}{s}[/tex]
Separation between plates [tex]d = 1.30 \times 10^{-2}[/tex] m
Area of plates [tex]A = 0.174[/tex] [tex]m^{2}[/tex]
From the formula of displacement current,
[tex]I_{d} = \epsilon _{o} A\frac{dE}{dt}[/tex]
We know that [tex]E = \frac{V}{d}[/tex].
So we can modify above formula,
[tex]I_{d} =( \frac{\epsilon _{o} A }{d} ) \frac{dV}{dt}[/tex]
Put the values in above equation,
[tex]I_{d} = ( \frac{8.85 \times 10^{-12} \times 0.174 }{1.30 \times 10^{-2} } ) \times 107[/tex]
[tex]I_{d} = 1.26 \times 10^{-5}[/tex] mA
Therefore, the displacement current between the plates is [tex]1.26 \times 10^{-5}[/tex] mA